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I need assistance I keep getting 2.53333 as an answer

=(10-8.1)/0.75=2.53333

The problem is as follows:
A pizza franchise specifies that the amount of cheese on a large pizza should be on average 10 ounces with a standard deviation of 0.75 ounces. An inspector measures the amount of cheese on a large pizza and finds the amount of cheese is 8.1 ounces. Assume the process of adding cheese is normally distributed.

*If the amount of cheese on the pizza is more than 1 standard deviation below the mean, the inspector must issue an "opportunity for improvement" citation.

*If the amount of cheese on the pizza is more than 3 standard deviations below the mean, the inspector must issue finsing.

*If the amount of cheese on the pizza is more than 3 standard deviations below the mean, the inspector must issue a finding.

What would the corresponding z-score for the amount of cheese found on the pizza and what action should the inspector take?

Z-score =

Round your final answer to two decimal places.

Select Whats is the inspectors action should be:
The inspector should issue finding
The inspector should issue a warning?
The inspector issue an opportunity for improvement"

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Solution Summary

The expert examines descriptive statistics for describing variation z-scores.

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