Mean and Standard Deviation

Related BrainMass Solutions

• Six Sigma and Process Development/Measurement

  Mean = 55 Standard Deviation = Variance^0.5=4^0.5=2.0 USL = 55+4=59 LSL=55-4=51 Cp = Tolerance / (6*standard deviation) = (USL-LSL)/standard deviation Cp=(59-51)/(6*2)=0.667 Cpk = Minimum of (USL-mean)/(standard deviation*3) and (mean-LSL)/(standard

• Sample mean and standard deviation of a manufacturer

  A test is made of 20 products and the sample time are shown below. Find the mean and the standard deviation of the sample.

• Confidence Intervals

  A student scores 33 on and English test that has a mean of 28 and a standard deviation of 5. He scores a 27 on a math test that has a mean of 25 and a standard deviation of 2. Which score is higher and why?

• What would be the mean, variance, standard deviation and shape of the distribution of sample means?

  population, sample mean distribution will follow normal distribution with mean=18 and standard deviation=0.5774 Solution discusses mean, standard deviation and variance of a given sampling distribution with formulas and calculations.

• Probability calculation using Normal Distribution

  If you changed the mean to 100 and the standard deviation to 10, what would Q's score be?

• Normal distribution

  Mean = 121 Standard deviation = 16 B. Mean = 121 Standard deviation = 3.2 C. Mean = 24.2 Standard deviation = 16 D.

• Why do we use standard deviation? Why do we use averages?

  Define standard deviation The standard deviation is the spread of the data around the mean.

• Sampling Distribution

  387734 Mean and standard deviation of the sampling distribution Random samples of size 17 are taken from a population that has 200 elements, a mean of 36, and a standard deviation of 8.

• Mean and standard deviation of normal distribution

  and standard deviation of the service life which is normally distributed.

• Standard Deviation

  and 16.98 Thus 70% (=7/10) is within 1 standard deviation of mean The expert calculates the standard deviation for a set of data and the percent of data that lies within one standard deviation of the mean.