Mean and standard deviation of normal distribution
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The service life of a certain product is normally distributed. Suppose 94 percent of the items have lives exceeding 2000 h and 3.51 percent have lives exceeding 16,240 h. Find the mean and standard deviation of the service life.
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The expert calculates the mean and standard deviation of the service life which is normally distributed.
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The service life of a certain product is normally distributed. Suppose 94 percent of the items have lives exceeding 2000 h and 3.51 percent have lives exceeding 16,240 h. Find the mean and standard deviation of the service life.
94% of the items have lives exceeding 2000 hrs
Therefore 6% of the items have lives upto 2000 hrs
Z corresponding to 6% is -1.5548
3.51% of the items have lives exceeding 16,240 hrs
Therefore 96.49% of the items have ...
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