Purchase Solution

Mean & S.D. of Sampling Distribution

Not what you're looking for?

Ask Custom Question

A population has a mean (Ã?µ) of 615 and a standard deviation (Ã?Æ') of 90. Assume that a sampling distribution of sample means has been

Constructed, based on repeated samples of n=400 from this population.
a). what would be the value of the mean of the sampling distribution?

b. what would be the value of the standard error of the mean?

Can you show me your work so I can understand this?

Purchase this Solution
Solution Summary

The solution provides step by step method for the calculation of mean and standard error of sampling distribution of sample means. Formula for the calculation is also included.

Solution Preview

Please see the attachment.

Standard deviation
A population has a mean (µ) of 615 and a standard deviation (σ) ...

Purchase this Solution
Free BrainMass Quizzes
Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.

Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.

Measures of Central Tendency

Tests knowledge of the three main measures of central tendency, including some simple calculation questions.

Know Your Statistical Concepts

Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.

View More Free Quizzes
Related BrainMass Solutions

  • Hypothesis testing problems

    The mean time was 28 minutes. One month later a sample of 127 customers was selected. The mean wait time recorded was 26.9 minutes and the S.D. of the sampling was 8 minutes.

  • Compute the mean

    5187 Compute the mean statistics 1) A test has the following properties: mean = 100, S.D. = 15, and r = .74. An individual has obtained a score of 85 on this test.

  • Standard deviations calculated

    Mean = 3.5 S.D.= 5 Sally's score = 1.5 Assuming this is a normal distribution, we aim to find the z - score. It will tell us how many SD's is sally away from the mean.

  • Sampling Distributions

    s.d. = 6.9/√25 = 6.9/5 = 1.38 b) the number of sample means that fall between 172.5 and 175.8 centimeters inclusive; Let's calculate z-scores like in problem 1, using the mean and standard deviation of the sampling distribution.

  • Normal distribution probability - Central Limit Theorem

    26785 Normal distribution probability - Central Limit Theorem Assume men's weights are normally distributed w/ a mean of 172 lb. and a s.d. of 29lb. (a) If one man randomly selected, find the probability his weight is between 166 and 176 lb.

  • Statistics: observed value, imperial rule, bar graph, random sample, sampling methods

    Stanford - Binet IQ score of 92 ( mean 100, s.d. =16) c. Woman's height of 68 inches (mean=65 inches, s.d. = 2.5 inches) 2- Use imperial rule to specify the ranges into which 68%, 95%, and 97% of Stanford - Binet IQ scores fall.

  • Calculating Standard Deviations and Confidence Intervals.

    (a) Calculate the mean, standard deviation, and confidence interval for menu preference assuming simple random sampling was used.

  • Comparing Two Different Normal Distributions

    Next we find Kyle's z-score for his score of 28 on the SAT z = (score - mean)/s.d. = (28 - 18)/6 = 1.67 Kyle's score is 1.67 standard deviations above the mean.

  • Distribution

    b)Mean is 63.6 and s.d. is 2.5; Club had requirement that women must be 70 inches tall-what % meets that?

View More Related Solutions