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# Hydrocarbon Emissions

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Plants emit gases that trigger the ripening of fruit, attract pollinators, and cue other physiological responses. The hydrocarbons emitted by the potato plant were measured and compared to the plant weight. Weight (x) was measured in grams and hydrocarbon emissions (y) were measured in hundreds of nanograms for 11 plants. Let alpha = 0.05.
X 57 85 57 65 52 67 62 80 77 53 68
Y 8.0 22.0 10.5 22.5 12.0 11.5 7.5 13.0 16.5 21.0 12.0

For the data in the previous question,
a. Find the regression equation
b. Find 1) the predicted amount of hydrocarbon emissions from
each of the potato plants, 2) the residual for each plant rounded to one
decimal place, and 3) give the sum or your residuals.
c. Find the predicted amount of hydrocarbon emissions to three
decimal places from potato plants with the following weights:
1. 59
2. 75
3. 90

plase give clear formulas and tables

##### Solution Summary

Plants emit gases that trigger the ripening of fruit, attract pollinators, and cue other physiological responses. The hydrocarbons emitted by the potato plant were measured and compared to the plant weight. Weight (x) was measured in grams and hydrocarbon emissions (y) were measured in hundreds of nanograms for 11 plants. Let alpha = 0.05.
X 57 85 57 65 52 67 62 80 77 53 68
Y 8.0 22.0 10.5 22.5 12.0 11.5 7.5 13.0 16.5 21.0 12.0

For the data in the previous question,
a. Find the regression equation
b. Find 1) the predicted amount of hydrocarbon emissions from
each of the potato plants, 2) the residual for each plant rounded to one
decimal place, and 3) give the sum or your residuals.
c. Find the predicted amount of hydrocarbon emissions to three
decimal places from potato plants with the following weights:
1. 59
2. 75
3. 90

plase give clear formulas and tables

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###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

##### Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.