If 8 castles (rooks) are randomly placed on a chessboard, compute the probability that one of the rooks can capture any of the others (i.e. no row or file contains more than one rook).
This one is also kind of fun:
I sat out my chess board with marshmallows as the rooks and what I find is there is only one spot available from the random placement of the seven rooks in which the last rook can go and not have a capture occur. The number of spaces available to the last rook was 64-7= 57 . The probability That I put the rook in the wrong spot was then 56/57 for the last rook. Looking at ...
This solution is provided in 353 words and uses examples as well as calculations to determine probability.