# Probability - Chess Game

If 8 castles (rooks) are randomly placed on a chessboard, compute the probability that one of the rooks can capture any of the others (i.e. no row or file contains more than one rook).

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This one is also kind of fun:

I sat out my chess board with marshmallows as the rooks and what I find is there is only one spot available from the random placement of the seven rooks in which the last rook can go and not have a capture occur. The number of spaces available to the last rook was 64-7= 57. The probability That I put the rook in the wrong spot was then 56/57 for the last rook. Looking ...

#### Solution Summary

This solution is provided in 353 words and uses examples as well as calculations to determine probability.

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