If 8 castles (rooks) are randomly placed on a chessboard, compute the probability that one of the rooks can capture any of the others (i.e. no row or file contains more than one rook).© BrainMass Inc. brainmass.com March 4, 2021, 6:24 pm ad1c9bdddf
This one is also kind of fun:
I sat out my chess board with marshmallows as the rooks and what I find is there is only one spot available from the random placement of the seven rooks in which the last rook can go and not have a capture occur. The number of spaces available to the last rook was 64-7= 57. The probability That I put the rook in the wrong spot was then 56/57 for the last rook. Looking ...
This solution is provided in 353 words and uses examples as well as calculations to determine probability.