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    Poisson Distributions

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    Assume the accidents occur at random according to a Poisson process a rate of one every two days.

    a) What is the probability that exactly two accidents will occur in a particular two-day interval?

    b) What is the probability that one will have to wait at least two days to observe the next two accidents?

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    I do not understand your answer in part b)
    Why we need to the probability when x=0 or x=1?
    If it says wait at least two days, is equal to X>2?
    In this case can I use the exponential distribution?
    I am confused how can I find the right landa (which indicates the average number of events in the given time interval.
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    Solution Preview

    Part (b) asks: What is the probability that one will have to wait at least two days to observe the next two accidents?

    Since it is asking for the probability to wait when the next two accidents occur, ...

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