# Mean and Variance of Binomial Distribution

Assume that X follows binomial distribution with parameters n and p. Find its mean and variance.

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#### Solution Preview

Solution. Since X~b(n,p), we have

P(X=k)=C(n,k)p^k(1-p)^(n-k)

where C(n,k)=n!/[k!*(n-k)!]

So,

E(X)=Sum{k=0,n}k*P(X=k)

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#### Solution Summary

Assume that X follows binomial distribution with parameters n and p. Find its mean and variance.

$2.19