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Mean and Variance of Binomial Distribution

Assume that X follows binomial distribution with parameters n and p. Find its mean and variance.

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Solution. Since X~b(n,p), we have
P(X=k)=C(n,k)p^k(1-p)^(n-k)
where C(n,k)=n!/[k!*(n-k)!]
So,
E(X)=Sum{k=0,n}k*P(X=k)
...

Solution Summary

Assume that X follows binomial distribution with parameters n and p. Find its mean and variance.

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