Assume that the life of a roller bearing follows a Weibull Distribution with parameters: Beta = 2 and delta = 10000 hours.
a) determine the probability that a bearing lasts at leasts 8000 hrs.
b) Determine the mean time until failure of a bearing.
c) If 10 bearings are in use and failures occur independently what is the probability that all 10 bearings last at least 8000 hours?
β = 2, δ = 10000; P(t, δ, β) = 1 - e^[-(t/δ)^β]
(a) P(8000, 10000, 2) = 1 - e^[-(8000/10000)^2] = ...
This solution goes through the concept of the life of a roller bearing within the context of probability.