Probability for tennis player that there are no more than three of eight serves in?
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A certain tennis player makes a successful first serve 67% of the time. Assume that each serve is independent of the others. If she serves 8 times, what's the probability that there are no more than three serves in?
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Solution Summary
This solution explains how to find the probability that there are no more than a certain number of successful serves in a tennis match.
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p(x <=3)
= P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3)
= C(8, 0)*0.67^0*(1-0.67)^8 + C(8, ...
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