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    Multiple choice questions in statistics

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    Question 1: Suppose a population is normally distributed with a mean of 200 and a standard deviation of 40. The probability that x> 190 is:

    .5987
    .4013
    .7671
    .0987

    Question 2: Another name for the normal distribution is:

    exponential distribution
    Gaussian distribution
    regular distribution
    healthy distribution

    Question 3: Values are uniformly distributed between 50 and 80. The height of this distribution is:

    .0333
    .0555
    .1285
    .0437

    Question 4: Suppose x is normally distributed with a mean of 56. Eighty percent of the values are greater than 48. The standard deviation is approximately:

    9.52
    15.38
    26.67
    40.00

    Question 5: Who of the following is not given some credit for developing or discovering the normal distribution?

    Pierre-Simon de Laplace
    Abraham de Moivre
    Karl Gauss
    Karl Pearson

    Question 6: Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. If the gasoline price at a particular location is randomly selected, the probability that the price is between $1.70 and $1.80 is:

    .1818
    .0182
    .3333
    .4072

    Question 7: Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. The mean gasoline price for this distribution is:

    $1.80
    $1.825
    $1.85
    .0182

    Question 8: Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. If the gasoline price at a particular location is randomly selected, the probability that the price is between $2.15 and $2.40 is:

    .0000
    .0182
    .3333
    .4545

    Question 9: Problems from which of the following binomial distributions can be worked by the normal curve because the approximation is good enough?

    n = 10, p = .50
    n = 12, p = .60
    n = 13, p = .70
    n = 14, p = .80

    Question 10: Which of the following distributions represent things that are "measured" as opposed to "counted"?

    disjoint distributions
    metered distributions
    discrete distributions
    continuous distributions

    Question 11: The normal curve is sometimes referred to as the:

    curve of inflection
    bell-shaped curve
    de Moivre's curve
    unipeaked curve

    Question 12: An appliance store sells washing machines and dryers among other things. The average sale on washers and dryers is $530 with a standard deviation of $100. Suppose that sales figures on washers and dryers are normally distributed. If a sale is randomly selected, the probability that it is between $650 and $700 is:

    .0705
    .3849
    .1652
    .8403

    Question 13: Suppose x is normally distributed with a standard deviation of 7. Seventy-one percent of the values are less than 45. The mean is:

    48.85
    41.15
    43.53
    46.47

    Question 14: In order to work a binomial distribution problem by the normal curve, what must be true?

    n?p> 7
    0 <=n
    square root of (npq) >= 2.75
    n> 5 and .4 <p< .6
    n> 5 and .4 <p< .6

    Question 15: Suppose a population is normally distributed with a mean of 200 and a standard deviation of 40. The probability that x< 150 is:

    .1069
    .2276
    .1056
    .3944

    Question 16: A researcher is working a binomial problem using a normal curve approximation.
    In the binomial problem, the researcher is trying to determine the probability of 51 <x< 56. In working the problem by the normal curve, the solution will be found at:

    50.5 <x< 56.5
    50.5 x 56.5

    51.5 <x< 55.5
    50.5 <x< 55.5

    Question 17: Suppose 41% of all workers in the telecommunications industry are satisfied with their work. If 63 telecommunications workers are randomly selected what is the probability that fewer than 23 are satisfied with their work?

    .1977
    .2743
    .2358
    .3023

    Question 18: A z score is:

    the distance a value is from the mean
    the number of standard deviations a value is above or below the mean
    the probability that a value has in a normal distribution
    the peakedness of the curve

    Question 19: An appliance store sells washing machines and dryers among other things. The average sale on washers and dryers is $530 with a standard deviation of $100. Suppose that sales figures on washers and dryers are normally distributed. If a sale is randomly selected, the probability that it is greater than $600 is:

    .7580
    .2943
    .2580
    .2420

    Question 20: Suppose 29% of all commuter cars leaving downtown at 5 P.M. are going somewhere other than home. If 45 commuter cars leaving downtown at 5 P.M. are tracked, what is the probability that more than 11 are going somewhere other than home?

    .1950
    .2486
    .6950
    .7486

    Question 21: Values are uniformly distributed between 50 and 80. The probability of x> 75 is:

    .0333
    .3333
    .1667
    .0000

    Question 22: Suppose the average hourly wage of a production line worker in a particular industry is normally distributed with a mean of $9.40. Sixty percent of the workers earn less than $10.25. The standard deviation is:

    $1.42
    $3.40
    $8.50
    $2.13

    Question 23: A researcher is working a binomial problem using a normal curve approximation.
    In the binomial problem, the researcher is trying to determine the probability of x >=13. In working the problem by the normal curve, the solution will be found at:

    X >= 12.5
    X >= 13.5
    12.5 <=x <= 13.5
    x> 13

    Question 24: Values are uniformly distributed between 50 and 80. The mean of this distribution is:

    .5000
    65
    70
    .0333

    Question 25: Suppose 57% of all shoppers use credit cards for their purchase in department stores. If 80 such shoppers are randomly selected, what is the probability that more than 49 use a credit card?

    .3106
    .1894
    .2578
    .2946

    © BrainMass Inc. brainmass.com April 3, 2020, 4:09 pm ad1c9bdddf
    https://brainmass.com/statistics/probability/101700

    Solution Preview

    Question 1
    Suppose a population is normally distributed with a mean of 200 and a standard deviation of 40. The probability that x> 190 is:
    0.5987
    0.4013
    0.7671
    0.0987

    Answer: 0.5987

    Mean=M = 200
    Standard deviation =s= 40
    x= 190
    z=(x-M )/s= -0.25 =(190-200)/40
    Cumulative Probability corresponding to z= -0.25 is= 0.4013
    Or Probability corresponding to x< 190 is Prob(Z)= 0.4013
    Therefore probability corresponding to x> 190 is 1-Prob(Z)= 0.5987 =1-0.4013
    0r= 59.87%

    Question 2
    Another name for the normal distribution is:
    exponential distribution
    Gaussian distribution
    regular distribution
    healthy distribution

    Answer: Gaussian distribution

    Question 3
    Values are uniformly distributed between 50 and 80. The height of this distribution is:
    0.0333
    0.0555
    0.1285
    0.0437

    Answer: 0.0333
    0.033333333 =1/(80-50)

    Question 4
    Suppose x is normally distributed with a mean of 56. Eighty percent of the values are greater than 48. The standard deviation is approximately:
    9.52
    15.38
    26.67
    40

    Answer: 9.52

    Mean=M = 56.00
    s=standard deviation= ? (to be determined)
    80% of the values are greater than x= 48
    Z corresponding to 20% (= 100%- 80.%) is -0.8416
    z=(x-M )/s or s=(x-M ) /z*s
    or s=(48-56)/-0.8416= 9.51

    Question 5
    Who of the following is not given some credit for developing or discovering the normal distribution?
    Pierre-Simon de Laplace
    Abraham de Moivre
    Karl Gauss
    Karl Pearson

    Answer: Karl Pearson

    Question 6
    Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. If the gasoline price at a particular location is randomly selected, the probability that the price is between $1.70 and $1.80 is:
    0.1818
    0.0182
    0.3333
    0.4072

    Answer: 0.1818
    probability= 0.1818 =(1.8-1.7)/(2.1-1.55)

    Question 7
    Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. The mean gasoline price for this distribution is:
    $1.80
    $1.83
    $1.85
    0.0182

    Answer: $1.83

    Mean = 1.83 =(1.55+2.1)/2

    Question 8
    Suppose gasoline prices are uniformly distributed across the country ranging from $1.55 to $2.10. If the gasoline price at a particular location is randomly selected, the probability that the price is between $2.15 and $2.40 is:
    0
    0.0182
    0.3333
    0.4545

    Answer: 0
    Since the range is beyond the distribution

    ...

    Solution Summary

    Answers multiple choice questions in statistics on the topics of normal distribution, binomial distribution, uniform distribution, z score etc.

    $2.19

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