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Normal Distribution of Average Life Expectancy

A recent study found that the average life expectancy of a person living in Africa is 53 years with a standard deviation of 7.5 years. If a person in Africa is selected at random, what is the probability that the person will die before the age of 65?

a. 94.52%
b. 82.89%
c. 94.95%
d. 88.49%

Solution Preview

M = 53, SD = 7.5, x = 65

z = (x - M)/SD

z = (65 - ...

Solution Summary

Problem solved.

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