Purchase Solution

# Sample Z Test

Not what you're looking for?

Directions:
Perform a one sample z test for a population mean using the p value approach. Be sure to state the hypothese and the significance leve, to compute the value of the test statistics, to obtain the p value and to state your conclusion.
Question:
In 1990, the average duration of long distance telephone calls originating in one town was 9.4 minutes. A long distance telephone company wants to preform a hypotheses test to determind whether the average duration of long distance phone calls has changed from the 1990 mean of 9.4 minutes. The mean duration for a ramdom sample of 50 calls originating in the town was 8.6 minutes. Do the data provide suggicient evidence to conclude that the mean call duration U, has changed from the 1990 mean of 9.4 minutes? Perform the appropriate hypothesis test using a signicance level of 0.20. Assume that sigma=4.8 minutes.

##### Solution Summary

Perform a one sample z test for a population mean using the p value approach. Be sure to state the hypotheses and the significance level, to compute the value of the test statistics, to obtain the p value and to state your conclusion.
Question:
In 1990, the average duration of long distance telephone calls originating in one town was 9.4 minutes. A long distance telephone company wants to preform a hypotheses test to determind whether the average duration of long distance phone calls has changed from the 1990 mean of 9.4 minutes. The mean duration for a ramdom sample of 50 calls originating in the town was 8.6 minutes. Do the data provide suggicient evidence to conclude that the mean call duration U, has changed from the 1990 mean of 9.4 minutes? Perform the appropriate hypothesis test using a signicance level of 0.20. Assume that sigma=4.8 minutes.

Solution provided by:
###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

##### Free BrainMass Quizzes

Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.

##### Measures of Central Tendency

Tests knowledge of the three main measures of central tendency, including some simple calculation questions.

##### Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.

##### Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.