Please see attachment for problem in proper format.
Suppose that a company CEO claims that more than ¾ of his employees carry a secondary health insurance. You decide to test his claim using a significance level of a = 0.02. A sample of 200 employees finds that 160 of them carry secondary health insurance. First, you set up your hypotheses as follows:
H0: p ≤ 0.75
H1: p > 0.75 (claim)
Then you compute your sample statistic, and get the following:
(see attached file for formulas)
Compute the probability of getting a sample statistic at least as extreme as z=1.63, and interpret this probability value. Remember that in a one-tailed test such as this, you do not need to multiply your p-value by two.
Choose one of the following:
a. The p-value is small enough to prove the claim
b. The p-value is not small enough to prove the claim
The solution provides step by step method for the calculation of p-value. Formulas for the calculation and Interpretations of the results are also included.