Hypothesis testing
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From the 18 readings I calculated that the mean time was 65.37 minutes and the standard deviation was 8.2, which was pretty close to the claim in the newspaper. But was it enough difference to call him a fraud? What I needed was an hypothesis test!
I used the "Student's t Distribution" because I have a small sample. I let my null hypothesis be: Ho:  = 60, and, since I want to prove that his mean time is greater than 60 minutes, I'll set up my alternate hypothesis like this: H1: µ > 60
If I find my sample "test statistic" and then test it against the critical value, I can determine, once and for all, whether I can safely reject the claim.
I think that an alpha of .05 should be adequate.
Assume Ho:µ = 60, H1: µ > 60
Input the key figures, then indicate whether or not to reject Ho.
1. t(critical) = ?
2. t(sample) = ?
3. Decision on Ho ?
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