Margin of Error that Corresponds to the Given Values

Find the margin of error that corresponds to the given values of n (times) and x (successes) and the degree of confidence: n=1400, x=420, 95%. Go 3 decimal places of precision. Does not want upper or lower limits wants to calculate value for E.

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Assume that a random sample is used to estimate a population proportion p. Find themargin of error E thatcorresponds to thegiven statistics and confidence level:
90% confidence; the sample size is 1600 of which 30% are successes
Themargin of error E= _____ (round to four decimal places as needed).

A national Retail Foundation survey found housholds intended to spend an average of $932 during the December holiday season. Assume thatthe survey included 850 households and thatthe standard deviation of the sample is $215.
A With 95% confidence, what is themargin of error?

"In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for a sample of 81 business students over a one week period. Assume the population standard deviation is 1.8 hours. With a 0.95 probability, themargin of error is approximately."

1) Solve formula for variable:
The formula for themargin of error to establish a confidence interval has been found mathematically to be:
e= z s / square root of n
Where: e = margin of error
z = critical value
s = sample standard deviation
n = sample size
Giv

What differentiates a z test statistic for a population from the z statistic for a sampling of means? Why the difference?
Consider a normal population with μ = 43 and σ = 5.2. Calculate the z-score for an x ̅ of 46.5 from a sample of size 16.
Find the critical value z a/2 thatcorresponds to thegiven confidence level.

1. Consider the following test of whether the coin is fair. Toss a coin three times, if the coin lands whether all heads or tails, reject the Ho: p=1/2. If P=4/5, What is the probability of type II error for this procedure?
2. A sample of 350 orders for takeout at a local pizzeria found out thatthe average cost of order w

5. A recent survey of 800 TV viewers found 44% watched NBC news. Themargin of error was reported as 3.4%. Using a 95% level of confidence, show how this margin of error was obtained.
, list =?, p=?,q=?,n=?, SE=?

(1) The confidence interval: 5.06 < sigma2 < 23.33 is for the population variance based on the following sample statistics:
n = 25, x-bar = 41.2, and s = 3.1
What is the degree of confidence? Use only integers, no % sign and no decimal places.
(2) Find themargin of error.
95% c