c = 1:96 (delta/sqrt n)
(c= 1.96 x populations standard mean/square root of sample size n)
What will happen about the margin of error when the sample size increases?
[Please see the attached question file.]
(1) First, from the Table of Areas under the Standard Normal Curve we note that 0.95 corresponds to a z- score of 1.96 ...
Step-by-step soltion is provided.