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Statistics - Margin of Error

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See the attached file.
1. Under the case that population standard deviation delta is known and sample size n > 30. Show the margin of error for a 95% confidence interval (CI) for population mean µ as follows

c = 1:96 (delta/sqrt n)

(c= 1.96 x populations standard mean/square root of sample size n)

What will happen about the margin of error when the sample size increases?

[Please see the attached question file].

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Step-by-step solution that determines the margin of error is provided.

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(1) First, from the Table of Areas under the Standard Normal Curve we note that 0.95 corresponds to a z- score of 1.96 ...

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