# Chi square test for association

See attached file.

Explanation and completion of 2.1, 2.2, & 2.3.

PART 2: Problems

Answer the questions in Part 2. Be sure to show every step of your work clearly and completely. Explain

your conclusions in clear language for someone who is not statistically numerate.

CASE # GNDR TRAK ADV LIKE STDY GPA HIGH SCHOOL SENIORS

1 1 1 19 2 5.5 0.55

2 1 1 17 4 5.8 0.63 GNDR = Gender

3 0 1 16 8 3.3 0.67 F = 1

4 0 1 17 6 4.7 0.71 M = 0

5 1 2 14 6 4.2 0.72 TRAK = Course of Study

6 1 1 15 8 6.7 0.76 1 = remedial

7 1 3 11 7 3.8 0.75 2 = vocational

8 0 2 20 7 3.5 0.79 3 = mainstream

9 1 2 12 6 5.7 0.79 4 = college prep

10 0 1 12 7 5.3 0.83 ADV = Home Advantage

11 1 2 7 7 6.3 0.88 ranked index of

12 0 2 7 8 5.1 0.91 resources

13 0 3 7 4 4.4 0.90 for education

14 1 3 6 5 5.6 0.92 LIKE = Attitude Toward Teachers

15 1 3 4 4 6.1 0.95 1 = does not like teachers

16 0 2 4 5 5.7 0.94 10 = likes teachers a lot

17 0 3 7 5 5.1 0.96 STDY = Study time

18 0 3 3 10 6.2 0.98 hours per week

19 1 1 21 3 2.9 0.50 GPA = Average Grades

20 1 4 21 8 4.5 0.50 as percentage

21 0 4 2 10 4.1 0.99

22 0 4 1 10 2.2 1.00

2.1 Analyze the relation between GNDR and LIKE using Chi-square.

A. Construct a 2x2 table for these data using "female" and "male' as the categories on GNDR, and "dislike" and "like" as the categories on LIKE (by collapsing 1-5 into "dislike" and 6-10 in "like"). Include the marginals in your table.

B. Is there a statistically significant relation between gender and attitude toward teachers? Explain and justify your answer.

C. Compute the column percents for the table in order to determine the pattern of this relation. Explain your analysis in natural language for a non-technical audience.

2.2 Analyze the relation between TRAK and STDY.

A. Construct a table for these data using the existing categories on TRAK, and collapsing the continuous values of STDY into four categories (<2.0, 2.0-3.9, 4.0-5.9, and >5.9). Include the marginals in your table.

B. Calculate the percentages for the table so that they illustrate the effects of TRAK on STDY.

C. Is there an association? What are the strength and direction of the relation?

2.3 A. Calculate phi for the data in the table you constructed for 2.1.

B. Calculate lambda for the data in the table you constructed for 2.1.

C. Interpret phi and lambda. Explain how these statistics increase your understanding of these data.

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#### Solution Summary

The solution provides step by step method for the calculation of chi square test for association. Formula for the calculation and Interpretations of the results are also included. Interactive excel sheet is included. The user can edit the inputs and obtain the complete results for a new set of data.