# Chi square test for association

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Use a .05 level of significance to test

w x y z

A 31 33 43 26

B 44 45 34 22

State the hypotheses being tested,the test statistic, and the p-value?

Critical value of the test statistic is ?

With ? degrees of freedom.

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##### Solution Summary

The solution provides step by step method for the calculation of chi square test for association. Formula for the calculation and Interpretations of the results are also included. Interactive excel sheet is included. The user can edit the inputs and obtain the complete results for a new set of data.

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Answer

The null hypothesis tested is

H0: There is no association between the rows and columns.

The alternative hypothesis is

H1: There is association between the rows and columns.

The test statistic used is where O is the observed frequency and E is the expected frequency.

The Expected frequencies are given below. They are calculated using ...

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