Hypothesis Testing using Chi Square test of independence
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This table lists the sugar content of two types of apples from three different orchards. At a=.05, test the claim that the sugar content of the apples and the orchard where they were grown are not related.
Sugar Content Orchard 1 Orchard 2 Orchard 3
Apple Type 1 3 2 7
Apply type 2 25 10 19
a. There is evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 12.592 > 1.191
b. There is evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 5.991 > 2.404
c. There is not evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 1.191 < 12.592
d. There is not evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 2.404 < 5.991
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Solution Summary
The solution tests the hypothesis that the sugar content of the apples and the orchard where they were grown are not related. Chi Square test of independence has been used.
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This table lists the sugar content of two types of apples from three different orchards. At a=.05, test the claim that the sugar content of the apples and the orchard where they were grown are not related.
Sugar Content Orchard 1 Orchard 2 Orchard 3
Apple Type 1 3 2 7
Apply type 2 25 10 19
a. There is evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 12.592 > 1.191
b. There is evidence to reject the claim that the sugar content of the apple type and the orchard number are not related because the test value 5.991 > 2.404
c. There is ...
Purchase this Solution
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