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# Diode Current Manipulation

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A schottky diode and a pn junction diode have cross sectional areas a=10^-4. The reverse saturation current density of the pn junction diode is 3x10^-8 A/cm^2. The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2. Determine the forward bias voltage in each diode required to yeild diode currents of 1mA.

If I use Jst=A*T^2*exp( (-q*phi|bn) / KT) to find the voltage for the Schottky diode, how do I find phi|bn from the given information?

IF I use J=q*Dn*npo/Ln+q*Dp*pno/Lp. How do I determine Ln, Lp, npo, pno, Dn, and Dp from the given information?

Thank you.

##### Solution Summary

A schottky diode and a pn junction diode have cross sectional areas a=10^-4. The reverse saturation current density of the pn junction diode is 3x10^-8 A/cm^2. The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2. Determine the forward bias voltage in each diode required to yeild diode currents of 1mA.

##### Solution Preview

"The reverse saturation current density of the pn jhunction diode is 3x10^-8 A/cm^2. The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2. "

This is a bit ambiguous. That's okay.

Here is a simple and straightforward solution to the problem.

I am not sure why you need all these complicated equations, I will give you a simple solution and I am sure it's right.

Although the current mechanisms in ...

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