1) A transverse traveling wave on a cord is represented by D = 0.48 sin (5.6x +84t) where D and x are in meters and t in seconds. For this wave determine (a) the wavelength (b) the frequency (c) velocity (magnitude and direction) (d) amplitude and (e) maximum and minimum speeds of particles of the cord.

Solution Preview

The wave equation is given by
D = A sin (kx +w t)
Where
A= amplitude = 0.48 m ( in this example)
k = wave number = 2 pi / lambda = 5.6 ( in this example)
w = 2 pi f = 84 ( in this example)

(a) the wavelength lambda

k = 2 pi / lambda = 5.6
therefore lambda = ...

Solution Summary

The solution calculates (a) the wavelength (b) the frequency (c) velocity (magnitude and direction) (d) amplitude and (e) maximum and minimum speeds of particles of the cord

A wave causes a displacement y that is given in meters according to y=(0.45) sin (8.0 * 3.14t - 3.14x), where t and x are expressed in seconds and meters.
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Please see the attached file for better formula representation.
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PART a. On ATTACHMENT #1, in the spaces shown after the parameters listed

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F(z,t) = g(z -vt) + h(z + vt)

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Shwo that f4 does not.
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