In the attached image, how is VDC across the load resistor found?

The practice test has an answer of 28.24 ignoring the ripple voltage. VDC across the resister is Vout right? So, Vsecondary - the voltage drop in the diode = Vout = VDC

So, if the secondary winding has 40voltage - .7V drop in the top resistor, that's 39.3V. How is 28.24 derived? Thank you.

Also, when asked for the power dissipated in the transistor, exactly which voltage and current is used in the calculation? Is it Ve and ie?

What is a varacter operated in the reverse saturation region? Is seems like the depletion region width is being controlled by a variable forward bias - why is this wrong?

The Transform factor is 3:1 so the output will be 120/3=40V "rms". If one wants to find the V peak to peak at the left he must multiply with 2 times sqrt[2] - 2 times because his wave goes from -Vp to +Vp (sine wave with negative and positive values).At the right of the T/F you we have Vp-p=2*sqrt[2]*40Vrms - Attention: That is at the coil from top to bottom! If you count from Top to the middle or from Middle to bottom it is 20 Vrms - so be careful

We take as reference the ground, which is the middle of the coil! After the Diodes all of the negatives has become positives we have ...

Solution Summary

This solution provides an explanation for finding Voltage using transform factor and reference to diodes and capacitors.

FIGURE 1(a) shows a power supply using a full-wavebridgerectifier circuit. The main supply is stepped down by the transformer T1 and the secondary voltage Vs rectified by the four diodes D1 -D4; diodes D1 and D3 conduct on one half cycle and D2 and D4 on the other. The diodes are provided in a single 4-pin bridge-rectifier pac

Please check my work and if incorrect give me the correct answer
Please refer to the problem stated in the attached file.
(For the full-waverectifier circuit shown below, the supply voltage is 18-V rms sinusoidal, Vdo is approximately 0.7V and R=120. What is the value for PIV?)
This is my solution:
Piv=2Vs-Vd
2*18sq

Q1. A 9 V power supply delivers 2 A to a resistive load. The a.c. supply is 230 V, 50 Hz and a bridgerectifier is used in conjunction with a 0. 047 farad reservoir capacitor.
Estimate:
(a) The peak-to-peak ripple voltage.
(b) The transformer secondary voltage if the total forward voltage
drop in the rectifier is 2 V at 2 A.

I've attached jpegs that show the circuits that I'm working with. My problem is that I don't know how to find the values of Ct and Rt for a specific firing angle. What formulas are needed? Is the calculation affected by the fact that there are two different loads (see circuits 1 and 2 jpegs)? What process must I go through to fi

A full-wavebridgerectifier circuit with a 1-kohms load operates from a 120-V (rms) 60-Hz household supply through a 10-to-1 step-down transformer having a single secondary winding. It uses four diodes, each of which can be modeled to have a 0.7-V drop for any current. What is the fraction of a cycle that each diode conducts? W

An AC sine wave is applied to the input of a fullwaverectifier. The output of the fullwaverectifier is then applied to a half waverectifier. The output of the half waverectifier will most closely resemble:
A) the original sine wave.
B) an inverted form of the original sine wave.
C) the output of the fullwaverectifier.

Determine the capacitance required in a half waverectifier to produce a ripple voltage less than 0.2V. Assume that the input is a 60Hz signal with maximum voltage VM=100V and the load resistance R= 10kW.
I'm confused. What formulas do I use and how do I solve this?

1. Two waves are traveling through the same container of nitrogen gas. Wave A has a
wavelength of 1.5 m. Wave B has a wavelength of 4.5 m. The speed of wave B must be________ the speed of wave A.
a. one-ninth
b. one-third
c. the same as
d. three times larger than
2. As the wavelength of a wave in a uniform medium inc

(See attached file for full problem description and figures)
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21.8
The figure shows a standing wave oscillating at 100 Hz on a string.
Part A : What is the wave speed?
21.5
A 40-cm-long tube has a 40-cm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. As the ins