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Calculation of Engine Power

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A four wheeled vehicle is to have a total mass of 1.5 tonnes and two axels with its wheels each having a mass of 65kg and a radius of gyration 500mm. The wheel tread diameter is 950mm. The coefficient of rolling resistance between the wheels and the road is 0.3. Calculate the engine power required such that the vehicle will have an acceleration of 0 to 80 km/hr in 3.5seconds. Then calculate the engine power to remain at 80 km/hr for the same distance travelled during the acceleration period.

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Total mass of the four wheeler (m) = 1.5 tonnes = 1500kg
Mass of each wheel (m_w) = 65 kg
Radius of gyration of each wheel (k) = 500mm = 0.5 m
Wheel tread diameter (d) = 950mm = 0.95m
Hence, radius (R) = 0.95/2 = 0.475 m
Coefficient of rolling resistance between road & wheels (mu) = 0.3

moment of inertia of each wheel about axle (I) = m_w*k^2 = 65*0.5^2 = 16.25 kg-m^2

Friction force (f) = mu *m * g = 0.3 * 1500 * 9.8 = 4410 N (This friction ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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