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Escape Speed

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Show that escape speed is the square root of 2 times as large as the orbital speed of an object in orbit just above the earth's surface.

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Solution Summary

This solution includes formulas and calculations, including Kepler's second law. The object orbit above the earth's surface is determined.

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Let Vo be the orbital speed and Ve be the Escape speed.
For the body to orbit the earth, the centrifugal force must balance it's weight. :et it orbit at a distance of one Earth radius Re.

m*Vo^2/Re = ...

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