Find out the mass of the air in a room 3.00m by 4.00m by 5.00m given that the temperature is 200 C at atmospheric pressure (1atm = 101000 Pa)
Given that, Universal gas constant R = 8.314 J/ mol K, Boltzmann’s constant kB = 1.38 x 10-23 J/K
Mass to mole ratio of air = 0.029 kg/mol
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We can use the ideal gas law to solve this problem, ie, PV = nRT Use this equation to find the number of moles (n) of air in the room of volume ...
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Please convert them
(a) 456 cal to joules
(b) 22.3 j to Calories
(c) 234 kj to Calories
(d) 12.4 Cal to joules
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