How do I find the resultant of the three displacement vectors in the drawing by means of the component method? If the magnitudes of the vectors are A= 5 m B=5 m and C= 4 m?

All the three vectors in the problem are as shown in the following figure.

Let be the resultant vector.
Then
You can solve the problem in two ways.

Method 1:
Resolve and into their perpendicular components along X and Y axes. Perform the addition or subtractions of these perpendicular components as follows.
I think you know how to resolve a vector.
See for example, resolving vector A into its components along X & Y axes.
The X-component of vector A is denoted by Ax and
Y-component by Ay.
These components are
Ax = A cos 600 along +ve direction of X-axis.
Ay = A sin 600 along +ve direction of X-axis.

Similarly resolve vector B into its ...

Solution Summary

Solution takes a diagram of 3 displacement vectors and shows how to find their resultant. Attached as a .doc file.

... Let the resultant vector R make an angle ∝ with x axis ... Thus equations (2) and (3) specify the vector R fully ... What is understood by multiplication of vectors ? ...

... units toward us thus the magnitude or resultant will be. ... The magnitudes of these three vectors are: A = 10.0 ... player using the component method of vector addition ...

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... ijij Note that when we add vectors numerically, each ... between a lightning flash and the resulting thunder if ... that the final displacement is the vector sum of ...

... A vector can be resolved in two mutually perpendicular directions ... i and are the unit vectors in x ... i + 1.66 j hence the resultant displacement is given ...

... the +x direction and we wish to compute the resulting magnetic field ... µ0 I dl × r ∫ B= , 4π C r 3. ... C is the x-axis and r is the displacement vector from (0.1 ...

... digit is , thus the absolute error is So the resultant's absolute error ... All that left is to calculate the sum of all the vectors: The displacement vector is: ...

... in terms of Legendre polynomials in spherical coordinates resulting in pure ... µo - µ) / (µ + 2 µo) (a3/r3) [Be -3(Ber) r/r2], with vector potential Ain = He ...