# Vector

1) A team of surveyors mark off distances represented by vectors of (85m, 55 degrees), (43m, 0 degrees) and (37m, 345 degrees). Solve for the resultant displacement.

2) Find the resultant force. (463 N, 137 degrees), (258 N, 268 degrees) and (379 N, 128 degrees)

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#### Solution Preview

A team of surveyors mark off distances represented by vectors of (85m, 55 degrees), (43m,0 degrees)and (37m,345 degrees). Solve for the resultant displacement.

Component is the horizontal (x) direction = (Magnitude) x (Cos phi )

Component is the vertical (y) direction = (Magnitude) x (Sin phi )

a) (85m, 55 degrees)

Magnitude = 85 m

phi = 55 degrees

x component = 48.75 m =85 Cos55

y component = 69.63 m =85 Sin55

b) (43m,0 degrees)

Magnitude = 43 m

phi = 0 degrees

x component = 43 m =43 Cos0

y component = 0 m =43 Sin0

c) (37m, 345 degrees)

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#### Solution Summary

The expert finds the resultant displacement and resultant force.