Vector
1) A team of surveyors mark off distances represented by vectors of (85m, 55 degrees), (43m, 0 degrees) and (37m, 345 degrees). Solve for the resultant displacement.
2) Find the resultant force. (463 N, 137 degrees), (258 N, 268 degrees) and (379 N, 128 degrees)
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A team of surveyors mark off distances represented by vectors of (85m, 55 degrees), (43m,0 degrees)and (37m,345 degrees). Solve for the resultant displacement.
Component is the horizontal (x) direction = (Magnitude) x (Cos phi )
Component is the vertical (y) direction = (Magnitude) x (Sin phi )
a) (85m, 55 degrees)
Magnitude = 85 m
phi = 55 degrees
x component = 48.75 m =85 Cos55
y component = 69.63 m =85 Sin55
b) (43m,0 degrees)
Magnitude = 43 m
phi = 0 degrees
x component = 43 m =43 Cos0
y component = 0 m =43 Sin0
c) (37m, 345 degrees)
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Solution Summary
The expert finds the resultant displacement and resultant force.