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"An artillery shell is fired with an initial speed of 1.80x10^3 m/s at a angle of 54.3 degrees above the horizontal and returns to its original level before impact. Neglecting air resistance, calculate the time it is in motion. And calculate the horizontal distance traveled."

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there are 2 components of velocity
<br>horizontal, which is u cos P, where P = 54.3°
<br>Verticle, which is u sin P
<br>
<br>u = 1800 m/s
<br>P = 54.3
<br>
<br>so u horizontal = u cos P = 1150.374 m/s......1
<br>and u ...

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