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Charged Particle in Constant Electromagnetic Field, Lorentz

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The motion of a charged particle in an electromagnetic field can be obtained by the Lorentz Equation for the force on a particle in such a field. If the electric field vector is E and the magnetic field vector is B, the force on a particle of mass m that carries a charge q and has a velocity v is given by:

F= qE + qv (cross product) B

Where we assume v<< c (the speed of light)

a.) If there is no electric field and the particle enters the magnetic field in a direction perpendicular to the lines of flux show that the trajectory is a circle with radius:

r = (mv)/(qB)

b.) Choose thr z axis to lie in the direction of B and let the plane containing E and B be the xy plane.

Then: B = Bk, E= Ey j + Ez k

Show that z(t) = zo = zo't + (qEz)/(2m) t2

Where z(0) = zo and z'(0) = zo'

c.) Continue the calculation and find x'(t) and y'(t); show that the time averages of these velocities are:
(x') = Ey/B, (y') = 0

d.) Integrate the velocitiy equations above (c) with the initial conditions:

x(0) = -(Am)/( qB); x'(0) = Ey/B; y(0) = 0y'(0) = A

Note I cannot label vectors but hopefully it is clear from the context which are vectors

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https://brainmass.com/physics/electricity-magnetism/charged-particle-in-constant-electromagnetic-field-lorentz-93338

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The solution is written in the attached file 93338.pdf

COMMENT FROM STUDENT:
Could you do the calculations using the unit vectors(i.j.k) and vector ...

$2.19
Similar Posting

The motion of a charged particle in an electromagnetic field can be obtained from the Lorentz equation for the force on a particle in such a field.

The motion of a charged particle in an electromagnetic field can be obtained from the Lorentz equation for the force on a particle in such a field.
If the electric field vector is E and the magnetic field vector is B the force on a particle of mass m that carries charge q and has velocity v is given by:

F = qE +qv X B

1.

If there is no electric field and the particle enters the magnetic field in a direction perpendicular to the lines of teh magnetic flux, show that the trajectory is a circle with radius

r = mv/qB = v/w

where w=gB/m is the cyclotron frequency

2.
Choose the z-axis to lie in direction of B and let the plane containing E and B be the yz-plane.
Thus:
B = Bk E = E_y j + E_z k

Show that the z-component of the motion is given by:

z(t) = z(0) + (z_dot(0))*t+(qE_z / 2m) * t^2

3.
Continue the calculation and obtain expressions for dx/dt and dy/dt Show that the time average of these velocity components are:

<dx/dt> = E_y/B <dy/dt> = 0

4.
Integrate the velocity equation from (3) and show (with appropriate initial conditions - see attached file) that:

x(t) = -A/w * cos(wt) + E_y/B *t
y(y) = A/w *sin (wt)

Plot the trajectory for the following cases:

A > E_y/B
A = E_y/B
A < E_y/B

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