Acceleration of an electron in an electric field
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Given: The charge on the electron is
qe = 1.60218 *10 ^-19 C.
Given: The mass of the electron is
me = 9.10939 * 10 ^-31 kg.
What is an electron's momentum, if it is
accelerated across a 6 mm potential difference
15.6 mV?
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Let's denote the potential difference by V. To fix the sign, let's define q V to be the increase in potential energy. Now, 15.6 millivolt is very small, perhaps you meant kilovolt or megavolt instead? Anyway, I'll work out the solution symbolically, all you have to do is to insert the value for the voltage in the final equation.
Note that the charge of the electron, q, is minus the figure given in the problem, but we know that the electron is accelerated so we don't have to bother about signs, we can just take the increase in kinetic energy to be |q|V. If the electron was initially at rest, the total energy will become:
E = m c^2 + |q| V (1)
The momentum of the electron ...
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