(a) As we convert 1 Ib to kg as 1 Ib = 0.4536 kg (2 dec pl)
4000 lb = 4000 x conversion factor (Ib - kg) = 4000 x 0.4536 kg
4000 Ib = 1814.4 kg
(b) 1 mph = 1.6093 km/h (4 dec pl) [1]
1 mph = 1.6093 x 1000 m/h = 1609.3 m/h
As one hour equals 3600 seconds we convert 1 mph to m/s equivalent
1 mph = 1609.3/3600 m/s
Thus
60 mph ...
Solution Summary
The solution explains how to determine the horsepower required to accelerate a 400 Ib car from rest to 60 mph in 10 seconds. Explicitly by answering the following
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