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Calculating with Newton's 2nd Law

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1. If a cord is pulled upward, making an angle of 27º with respect to the horizon line, produces a force of 365N and can pull a box over the floor with a weight of 55.2 kg at a constant speed of 20.5 centimeters/sec - which is the magnitude of the friction force that opposes the movement of the box?
2. A boat pulls a water-skier at a constant speed of 13.5 meters/seconds. The tension of the cable is 165N - which is the magnitude of the friction force that the water and the air produces against the skier?
3. A parachuter of 72 Kilograms falls at a constant speed of 9.1 meters per second. The parachute has a mass of 6.5 Kilograms - a) What is the parachuter's weight? b) How big is the ascendant force that the air exercises on the parachuter and on the parachute?
4. A car of 1,270 Kilograms requires a horizontal force of 4770N to accelerate 0.175meters/seconds2 on a horizontal road. Which is the magnitude of the force that opposes said movement?
5. A car of 1,060 kg can accelerate from 0 to 80 kilometers in 9.4 seconds - How much force must should be exercise on the vehicle in order to obtain this acceleration?
6. A car pulls another car that weights 1,730 kilograms, if the car that is pulled must accelerate uniformly from 0 to 2.3 meter per second ... in 10.3 seconds ... How much force must be exercised by the pulling cable?
7. A car of 1570 kg moving at 17.5 meter/second must stop at 94.5 meters. What is the force?

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Solution Summary

The solution involves various calculations using Newton's 2nd Law, including calculations for friction force, weight, gravitational force and acceleration.

Solution Preview

1.) Because, the box has zero acceleration, therefore, along the plane (see attached figure),
Force of the cord F = mgsin(27) + f
(Because, F-mgsin(27)-f = m*a, a =0)
friction force,
f = F - mgsin(27) = 365 - 55.2*9.8*sin(27) = 119.41 N --Answer

2.) Because, the speed is constant, therefore,
the friction force = Applied force = 165 N --Answer
(Because, F-f = m*a, a =0)

3.) mass of man M = 72 kg
v(constant) = 9.1 m/s
mass of parachute m = 6.5 kg
a.) Parachuer's weight,
W = Mg ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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