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Upward Acceleration

Mass m1 (34.50 kg) is on a horizontal surface, connected to mass m2 (5.90 kg) by a light string. The pulley has negligible mass and no friction. A force of 220.9 N acts on m1 at an angle of 34.50 degrees. The coefficient of kinetic friction between m1 and surface is .233. Determine the upward acceleration of m2.

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To do this, you must consider each block separately, and the forces acting upon each.

So, first let's consider the forces acting on block 1. Further, let's consider the x and y components separately.

BLOCK 1, x direction, with positive direction to the right:

Forces on block 1 in the x direction are:

- the x-component of the applied force F, which, from trigonometry, is F*cos(theta).
- the force of friction, which is to the left, so we'll call that -f_k
- the tension in the string, which is also pulling to the left, so we'll call that -T

These are the three ...

Solution Summary

The solution looks at this problem of upwards acceleration via a pulley by breaking it down into the two blocks and the force in the x and y direction on each in a helpful manner that makes it easy to follow the calculations to the conclusion.

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