Explore BrainMass

Explore BrainMass

    scattering angle, wavelenght, and speed for the electron

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    See attached file for further details.

    3. A 0.650 MeV photon scatters off a free electron such that the scattering angle of the photon is twice the scattering angle of the electron (Fig. P40.31).

    (a) Determine the scattering angle for the electron.
    [ ]°
    (b) Determine the final speed of the electron.
    [ ]c

    4. A photon having wavelength lamda scatters off a free electron at A (Fig. P40.32), producing a second photon having wavelength lamda'. This photon then scatters off another free electron at B, producing a third photon having wavelength lamda" and moving in a direction directly opposite the original photon as shown in Figure P40.32. Determine the numerical value of delta(lamda) = lamda" - lamda.
    [ ] nm

    © BrainMass Inc. brainmass.com March 4, 2021, 8:27 pm ad1c9bdddf


    Solution Summary

    The solution shows how to calculate the scattering angle, speed, and the wavelength of the electron, which is scattered off by a photon (see attachment).