"The work function of gold is 4.58 eV. What frequency of light must be used to eject electrons from a gold surface with a maximum kinetic energy of 6.48e-19?"
Here's what I did:
W0 = (4.58 eV) (1.6e-19) = 7.33e-19 J
Kmax = hf - W0
f = (Kmax / h) + W0
f = (6.48e-19 / 6.626e-34) + 7.33e-19 = 9.78e14 Hz
But that's not the right answer. The right answer is supposedly 2.08e15.© BrainMass Inc. brainmass.com August 20, 2018, 2:16 pm ad1c9bdddf
Your setup is totally fine. Your equations are correct. Your ...
This solution provides a brief outline on the mistake in the problem, involving frequency calculations.