1. A bead slides without friction around a loop-the-loop. The bead is released from a height of 8.5 m from the bottom of the loop-the-loop which has a radius 3 m.The acceleration of gravity is 9.8 m/s. What speed is it at point a?
2. A bobsled slides down an ice track starting (at zero initial speed) from the top of a(n) 171 m high hill. The acceleration of gravity is 9.8 m/s. Neglect friction and air resistance and determine the bobsled's speed at the bottom of the hill.
3. A girl swings on a playground swing in such a way that at her highest point she is 2.4 m from the ground, while at her lowest point she is 0.8 m from the ground. What is her max speed?
4. A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 1.0 m/s. The acceleration of gravity is 9.81 m/s. What was the initial height of the bob?© BrainMass Inc. brainmass.com March 22, 2019, 1:09 am ad1c9bdddf
The bead has originally a potential energy m*g*H.
½(mvo²) = m*g*H.
½(mvo²) = mgH = ½(mv1²) + mg(2r)
v1 = sqrt(2*(H - 2r)*g) = ...
The acceleration for kinematic problems are examined. The expert examines the slides without friction around a loop-the-loop.