1. A bead slides without friction around a loop-the-loop. The bead is released from a height of 8.5 m from the bottom of the loop-the-loop which has a radius 3 m.The acceleration of gravity is 9.8 m/s. What speed is it at point a?
2. A bobsled slides down an ice track starting (at zero initial speed) from the top of a(n) 171 m high hill. The acceleration of gravity is 9.8 m/s. Neglect friction and air resistance and determine the bobsled's speed at the bottom of the hill.
3. A girl swings on a playground swing in such a way that at her highest point she is 2.4 m from the ground, while at her lowest point she is 0.8 m from the ground. What is her max speed?
4. A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 1.0 m/s. The acceleration of gravity is 9.81 m/s. What was the initial height of the bob?© BrainMass Inc. brainmass.com October 25, 2018, 8:05 am ad1c9bdddf
The bead has originally a potential energy m*g*H.
½(mvo²) = m*g*H.
½(mvo²) = mgH = ½(mv1²) + mg(2r)
v1 = sqrt(2*(H - 2r)*g) = ...
The acceleration for kinematic problems are examined. The expert examines the slides without friction around a loop-the-loop.
Summary of kinematics, solutions to kinematics problems.
Here, we provide a brief summary of some common kinematics, and solve three common kinematics problems, specifically from College Physics, by J. Serway, et al. We specifically find:
For a car traveling east at a given velocity, the final velocity for a constant acceleration in two different directions.
For an arrow shot straight up in the air, the maximum height of the arrow and the time the arrow is in the air.
For a mailbag released from a descending helicopter, the speed of the mailbag and its distance below the helicopter.
We focus on the strategy for solving kinematic equations efficiently. The full solution/explanation is included in both PDF and PS format.View Full Posting Details