Ray Optics: Concave mirror
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Concave mirror is placed near one end of an optical bench. It is aimed to make an image offside from the light source projected onto a screen.
Initially the light source is placed 3 m from the mirror. The screen is moved until the image comes into focus on the screen.
What would be the approximate object distance p (distance from image to vertex of mirror)?
What would be the approximate image distance q (distance from screen to vertex of mirror)?
The light source is moved 3 cm closer to the mirror. The screen is moved accordingly.
What would be the new values of p and q? Find p and q for 6 intervals of 3 cm (closer to mirror).
(b) Plot q vs. p
(c) Plot data again in a matter that yields a straight line. For a straight line, y = mx +b, therefore plot 1/q vs. 1/p. Determine focal length from intercepts with both x-axis and y-axis. What is it?
Hint: Relate 1/q = -1/p = 1/f
(d) What is the radius of curvature of the mirror?
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Solution Summary
The object distances and the image distances and their inverses are plotted and the radius of curvature of the mirror is calculated.
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Concave Mirror problem
Please answer and explain the following
(Hi. Thanks for your message. We weren't given an initial image distance, so please pick a distance of your choosing in order to the solve the problem. I will extend the deadline.)
Concave mirror is placed near one end of an optical bench. It is aimed to make an image offside from the light source projected onto a screen.
Initially the light source is placed 3 m from the mirror. The screen is moved until the image comes into focus on the screen.
What would be the approximate object distance p (distance from image object to vertex of mirror)?
What would be the approximate image distance q (distance from screen to vertex of mirror)?
The light source is moved 3 cm closer to the mirror. The screen is moved accordingly.
What would be the new values of p and q? Find p and q for 6 intervals of 3 cm (closer to mirror). ...
Purchase this Solution
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