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forces among the three wagons

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A locomotive is pulling three wagons along a level track with a force of 100,000 N. The wagon next to the locomotive has a mass of 80,000 kg, the next one, 50,000 kg, and the last one, 70,000 kg. Neglect friction. What is the force between the 80,000-kg and 50,000-kg wagons?
35,000 N
40,000 N
60,000 N
65,000 N

A locomotive is pulling three wagons along a level track with a force of 100,000 N. The wagon next to the locomotive has a mass of 80,000 kg, the next one, 50,000 kg, and the last one, 70,000 kg. Neglect friction. What is the force between the 50,000-kg and 70,000-kg wagons?
35,000 N
40,000 N
60,000 N
65,000 N

A locomotive is pulling three wagons along a level track with a force of 100,000 N. The wagon next to the locomotive has a mass of 70,000 kg, the next one, 50,000 kg, and the last one, 80,000 kg. Neglect friction. What is the force between the 80,000-kg and 50,000-kg wagons?
35,000 N
40,000 N
60,000 N
65,000 N

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Solution Summary

The solution shows how to compute the forces among the three wagons, which are pulled by a locomotive.

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See Also This Related BrainMass Solution

Applying Newton's Law for a wagon (M) attached by string with hanging mass (m) through frictionless pulley.

See the attachment for a diagram and the data in a chart before answering the following problem.

The mass of the wagon (M) and the hanging mass (m) are in kilograms. The total mass of the system is Mt, the sum of M and m. The acceleration of gravity (g) is 9.8 m/s2 . The acceleration of the system (a) varies, depending upon the experimental values of M, m, and µ. In the situation shown above (μ = 0), the only force acting on the system is the weight of the hanging mass, Wm.

Fill in the following table, using the value of a obtained from the simulation. Record and calculate data to the nearest three decimal places. The masses in the table are in kg, but the input data are in grams, so make the necessary conversions. The first row has been completed for you.

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