When a system is taken from state a to state b in the figure View Figure along the path acb, the amount of heat that flow into the system is 95.0 J and the work done by the system is 57.0 J.

A) How much heat flows into the system along path adb if the work done by the system is 10.0 J?

B) When the system is returned from b to a along the curved path, the absolute value of the work done by the system is 32.0 J. How much heat does the system liberate?

C) If the internal energy is zero in state a and 13.0 J in state d, find the heat absorbed in the processes ad.

"When a system is taken from state a to state b in the figure View Figure along the path acb, the amount of heat that flows into the system is 95.0 J and the work done by the system is 57.0 J."

This means that the internal energy change is:

Delta U = Q - W = 95 J - 57 J = 38 J

The internal energy U is a so-called "state function" (or state variable). This just means that if the complete thermodynamic state is specified, the internal energy is determined by that. The thermodynamic state is specified by the pressure and volume or pressure and temperature, etc.. In this case this means that we can conclude from Delta U = 38 J that:

... By ideal gas equation : PV = nRT = RT (as n = 1 mole ... 400 x 8.31 = + 3324 J (by convention work done by ... Temperature rises from 400K to 800 K. Heat flows into the ...

... its original volume, nitrogen behaves as an ideal gas under these ... energy of the gas and the work done in ... conditions, Q=0 (there is no heat transfer from or ...

Heat Transfer and Work Done During Polytropic Process. ... a) Calculate the heat transfer for the process. ... in detail including integrals (assume an ideal gas). ...

... temperature) - that can be derived from the ideal gas law ... one equilibrium state to another and the work that is ... on or by the system, and how heat flows into or ...

... the total work done by moving the system from state A to state B is: (1.4) We see that for expansion ( ) the work done is ... The heat that flows into the ...

... 105 Pa and 355 K. The oxygen may be treated as an ideal gas. ... (d) Compute the total work done by the ... (e) Find the absolute value of the total heat flow into or ...

... So, there is no exchange of heat from the container wit the ... Nor is any work done by the container. ... When we remove the wall, the gas will flow out rapidly into ...

... 161 kJ/kg (negative sign implies heat is flowing out of the ... Net work done = -160 + 150 + 160 = 150 kJ/kg. ... at state 1. 3→4 Constant volume heat rejection until ...

... The sudden compression is not allowing the heat to transfer, and hence ... external agency has to apply a force and displacec the piston, means doing the work. ...