A) How much heat flows into the system along path adb if the work done by the system is 10.0 J?
B) When the system is returned from b to a along the curved path, the absolute value of the work done by the system is 32.0 J. How much heat does the system liberate?
C) If the internal energy is zero in state a and 13.0 J in state d, find the heat absorbed in the processes ad.
D) Find the heat absorbed in the processes db.© BrainMass Inc. brainmass.com October 24, 2018, 9:43 pm ad1c9bdddf
"When a system is taken from state a to state b in the figure View Figure along the path acb, the amount of heat that flows into the system is 95.0 J and the work done by the system is 57.0 J."
This means that the internal energy change is:
Delta U = Q - W = 95 J - 57 J = 38 J
The internal energy U is a so-called "state function" (or state variable). This just means that if the complete thermodynamic state is specified, the internal energy is determined by that. The thermodynamic state is specified by the pressure and volume or pressure and temperature, etc.. In this case this means that we can conclude from Delta U = 38 J that:
U(b) - U(a) = Delta U = 38 ...
A detailed solution is given.
Thermodynamic process problem
A The drawing refers to one mole of a monatomic ideal gas and shows a process that has four steps, two isobaric (A to B, C to D) and two isochoric (B to C, D to A). Complete the following table by calculating U, W, and Q (including the algebraic signs) for each of the four steps and for the whole process.View Full Posting Details