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    Nitrogen balloon: volume, number of moles, mass of nitrogen

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    A round balloon had a radius of 0.30 m & contains nitrogen (N2) at 30 degrees Celsius and one atmosphere total pressure. a) What is the volume of the nitrogen in the balloon?
    b) How many moles of nitrogen are in the balloon?
    c) What is the mass of the nitrogen in the balloon?
    d) If the balloon is then submerged in a body of fresh water to a depth of 25 meters where the water temperature is 7 degrees Celsius, what is the volume of the nitrogen in the balloon at the depth of 25 meters?

    © BrainMass Inc. brainmass.com October 6, 2022, 2:22 pm ad1c9bdddf
    https://brainmass.com/physics/ideal-gas-law/nitrogen-balloon-volume-number-of-moles-mass-of-nitrogen-40529

    SOLUTION This solution is FREE courtesy of BrainMass!

    Volume of Nitrogen:

    radius of balloon= 0.3 m
    Volume of balloon= (4/ 3 ) pi r ^3 = 0.1131 m^3
    Therefore Volume of Nitrogen in the balloon= 0.1131 m^3

    No of moles of Nitrogen:

    Volume=V= 0.1131 m^3
    Pressure=P= 1 atm= 101350 N / m^2
    Temperature= T= 30 degrees C= 303.15 K =273.15+30
    Ideal gas Law is PV=nRT
    or n=PV/RT
    R= Gas constant= 8.3145 J.mol ^-1K ^-1
    Therefore
    No of moles=n= 4.55 moles =(101350*0.1131)/(8.3145*303.15)
    There are 4.55 moles of Nitrogen in the balloon

    Mass of Nitrogen:

    No of moles = 4.55 moles
    1 mole of Nitrogen (N2)weighs 28 gms
    Therefore 4.55 moles of Hydrogen weigh 127.4 gms =4.55*28
    or 0.1274 kg

    Volume of the nitrogen in the balloon at the depth of 25 meters:

    Pressure at this depth = Atmospheric pressure + Pressure of water= h rhog
    h= 25 m
    rho= 1000 kg/m^3
    g= 9.81 m/s^2

    Pressure of water= 245250 N/m^2 =25*1000*9.81

    Total pressure= 346600 N/m^2 =101350+245250

    no of moles=n= 4.5500 moles
    Pressure=P= 346600 N / m^2
    Temperature= T= 7 degrees C= 280.15 K =273.15+7
    Ideal gas Law is PV=nRT
    or V=nRT/P
    R= Gas constant= 8.3145 J.mol ^-1K ^-1
    Therefore
    Volume=V= 0.03060 m^3 =(4.55*8.3145*280.15)/346600

    Volume of nitrogen= 0.03060 m^3

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com October 6, 2022, 2:22 pm ad1c9bdddf>
    https://brainmass.com/physics/ideal-gas-law/nitrogen-balloon-volume-number-of-moles-mass-of-nitrogen-40529

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