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Hydrodynamics: Bernoulli's equation and fluid flow,

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If for the pipe carrying water in a building, h = 144 meters, v1 = 2.88 m/s, and the cross-sectional area at 1 is twice that at 2, what must P1 be, to the nearest K Pa, in order that P2 = 101000 Pa?

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If for the pipe carrying water in a building, h = 144 meters, v1 = 2.88 m/s, and the cross-sectional area at 1 is twice that at 2, what must P1 be, to the nearest KPa, in order that P2 = 101000 Pa?

The velocity of water at point 2 can ...

Solution Summary

Pressure difference for a pipe with water flowing through it is calculated.

$2.19