A heat engine (thermodynamic cycle) with a fixed amount of working gas is shown in diagram. If the gas temperature at point 3 is 400 K, then how many moles of gas are in the engine? What is the temperature at point 2? Is process stroke 2,3 a heat intake or cooling stroke? How much work is done by process stroke 2,3? How much net work is produced for the whole cycle?© BrainMass Inc. brainmass.com October 24, 2018, 6:26 pm ad1c9bdddf
1) Use PV=nRT (R = 8.315 J/molK)
n = PV / RT
In this case:
T = 400K
P = 200e3 Pa
V = 0.005m^3
n = (200e3)(0.005) / (8.315 * ...
This solution uses the formula PV=nRT and includes complete calculations and answers. The net work for the whole cycle is determined.
Thermodynamics: Change in entropy for a heat engine
A heat engine operates between two reservoirs at T_2= 600K and T_1= 350K. It takes in 1000J of energy from the higher-temperature reservoir and performed 250 J of work. Find the entropy change of the universe and the work that could have been done by an ideal Carnot engine operating between these two reservoirs.
I've tried (Q_h/T_h)- (Q_c/T_c). My answer is incorrect. I come up with 1. something instead of .476 J/K. Can you help?View Full Posting Details