Neglect end effects. The region between the conductors is air. Ke =1/4*pi*epsilon= 8.98755e9 N m^2/C^2.
A coaxial cable has a charged inner conductor (with charge +4.8 microcoulombs and radius 1.199 mm) and a surrounding oppositely charged conductor (with charge -4.8 microcoulombs and radius 7.405 mm).
a) What is the magnitude of the electric field halfway between the two cylindrical conductors in V/m?
b) What is the capacitance of this cable in nF?© BrainMass Inc. brainmass.com March 4, 2021, 5:44 pm ad1c9bdddf
See attached graph.
According to Gauss theorem:
Within the Guassian surface:
Flux = charge inside the surface/epsilon
E*2pi*r*l = Q/epsilon
=> E(electric field strength) = Q/(2pi*r*e*l)
here, e =epsilon
=> E = ...
With formulas and calculations, the problems are solved.