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    Coaxial cable: Magnitude of the electric field; capacitance of the cable

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    Neglect end effects. The region between the conductors is air. Ke =1/4*pi*epsilon= 8.98755e9 N m^2/C^2.

    A coaxial cable has a charged inner conductor (with charge +4.8 microcoulombs and radius 1.199 mm) and a surrounding oppositely charged conductor (with charge -4.8 microcoulombs and radius 7.405 mm).

    a) What is the magnitude of the electric field halfway between the two cylindrical conductors in V/m?

    b) What is the capacitance of this cable in nF?

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    https://brainmass.com/physics/flux-flux-density/coaxial-cable-magnitude-of-the-electric-field-capacitance-of-the-cable-8988

    Solution Preview

    See attached graph.

    According to Gauss theorem:
    Within the Guassian surface:
    Flux = charge inside the surface/epsilon
    E*2pi*r*l = Q/epsilon
    => E(electric field strength) = Q/(2pi*r*e*l)
    here, e =epsilon
    => E = ...

    Solution Summary

    With formulas and calculations, the problems are solved.

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