If each fission of a 235nucleons 92protonsU nucleus releases about 2.0e2 MeV of energy, determine the energy (in joules) released by the complete fissioning of 0.9 gram of 235nucleons 92protonsU.
Solution Preview
Energy per fission = 200 MeV = 200 * 1.6022*e-13 Joules
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Solution Summary
The solution uses simple, easy-to-understand equations to find the answer to the question posed about fission reaction emissions energy.
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