# Tension Problem

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A loudspeaker of mass 25.0 kg is suspended a distance of h= 1.00m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l= 4.00 m.

What is the tension in each of the cables?

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## SOLUTION This solution is **FREE** courtesy of BrainMass!

Using the equilibrium at vertical forces, we have:

T1sin(theta) + T2sin(theta) - mg = 0

Using the dimensions of the string, we have:

sin(theta) = 1/4 = 0.25

Using the equilibrium at horizontal forces, we have:

T1cos(theta) - T2cos(theta) = 0

Since theta for both are equal then,

T1 = T2 = T

Solving for T, we have:

T(0.25) + T(0.25) - 25(9.81) = 0

0.5T = 245.25

T = 122.625N

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