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    Rotational motion

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    A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates freely with an angular speed of .667 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.38 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim.

    Calculate the initial and final kinetic energies of this system.

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    Solution Preview

    Merry-go-round (r=2.63 m, m = 155 kg) 3.38 m/s Person (mass 59.4 kg)

    0.667 rev/s

    The moment of inertia of the merry-go-round (assumed to be a round disc of uniform density) is I = ½ MR2 = ½  155  2.632 = 536 kg m2.

    The angular speed of the merry-go-round is ω = 2πf, where f is the ...

    Solution Summary

    The expert calculates the initial and final kinetic energies of the system merry-go-round. A step by step solution provided.