# Physics - Mechanics - Rotational Motion

A 1.2 kg grindstone in the shape of a uniform cylinder of radius 0.25 m acquires a rotational rate of 1800 rev/s from rest over a 6.0 s interval at constant angular acceleration. Calculate the torque delivered by the motor.

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#### Solution Preview

M = 1.2 kg, R = 0.25 m, w1 = 0, w2 = 1800 rev/s = 1800 (2pi) rad/s

= 11309.7 ...

#### Solution Summary

The expert examines the rotational motion for classical motion. Complete, neat, step-by-step solution is provided.

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