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    Energy and momentum methods

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    Solution Preview

    By momentum law:
    mb*ub + ma*ua = mb*vb + ma*va
    where, ua and ub are the velocities of blocks A and B, before impact and va and vb are the velocities after impact.
    ua = 0
    ub = 6 ft/s
    ma = 1.5 lb
    mb = 2.5 lb
    2.5*6 + 0 = 2.5*vb + 1.5*va
    => ...

    Solution Summary

    The solution is given in a step-by-step equational process and both momentum law and Newton's experimental law are used.