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# Energy and momentum methods

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##### Solution Summary

The solution is given in a step-by-step equational process and both momentum law and Newton's experimental law are used.

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By momentum law:
mb*ub + ma*ua = mb*vb + ma*va
where, ua and ub are the velocities of blocks A and B, before impact and va and vb are the velocities after impact.
ua = 0
ub = 6 ft/s
ma = 1.5 lb
mb = 2.5 lb
hence,
2.5*6 + 0 = 2.5*vb + 1.5*va
=&gt; ...

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###### Education
• MSc , Pune University, India
• PhD (IP), Pune University, India
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