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# Photons of energy impinging upon helium ions

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Photons of energy 65.561eV and 52.324eV impinge upon a collection of helium ions (He* , Z = 2).

a. Can the photons of energy 65.561eV be absorbed by the helium ions without ejecting the electron from the ions if the electron is initially in the ground state? If so, to which state is the electron promoted? If not, why not?

b. Can the photons of energy 52,324eV be absorbed by the helium ions without ejecting the electron from the ions if the electron is initially in the ground state? If so, to which state is the electron promoted? If not, why not?

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This solution of two part answers discusses the rate at which photons impinge upon a collection of helium ions.

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When an atom has only one electron, it is like a regular Hydrogen atom. The only possible difference is that instead of having a charge of +1 on the nucleus (Z), it might have +2 or something else. An atom that has just one electron is called a hydrogenic atom. The energy levels for hydrogenic atoms are given by the following formula, according to the Bohr model: energy in eV = -13.6 x Z^2/n^2. (-13.6 times Z squared over n squared). When we have a Helium He+ ION, it has just one electron so we can use this formula, with ...

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